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8p^2-2=15p
We move all terms to the left:
8p^2-2-(15p)=0
a = 8; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·8·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-17}{2*8}=\frac{-2}{16} =-1/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+17}{2*8}=\frac{32}{16} =2 $
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